2y^2-8x-12y+10=0

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Solution for 2y^2-8x-12y+10=0 equation:


Simplifying
2y2 + -8x + -12y + 10 = 0

Reorder the terms:
10 + -8x + -12y + 2y2 = 0

Solving
10 + -8x + -12y + 2y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -8x + -12y + -10 + 2y2 = 0 + -10

Reorder the terms:
10 + -10 + -8x + -12y + 2y2 = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -8x + -12y + 2y2 = 0 + -10
-8x + -12y + 2y2 = 0 + -10

Combine like terms: 0 + -10 = -10
-8x + -12y + 2y2 = -10

Add '12y' to each side of the equation.
-8x + -12y + 12y + 2y2 = -10 + 12y

Combine like terms: -12y + 12y = 0
-8x + 0 + 2y2 = -10 + 12y
-8x + 2y2 = -10 + 12y

Add '-2y2' to each side of the equation.
-8x + 2y2 + -2y2 = -10 + 12y + -2y2

Combine like terms: 2y2 + -2y2 = 0
-8x + 0 = -10 + 12y + -2y2
-8x = -10 + 12y + -2y2

Divide each side by '-8'.
x = 1.25 + -1.5y + 0.25y2

Simplifying
x = 1.25 + -1.5y + 0.25y2

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